यदि (f(x)=x-2-9) और (g(x)=x+3) हैं तो (\left\(\frac{f}{g}\right\)(-3)) के बारे में सही कथन क्या है?

If (f(x)=x-2-9) and (g(x)=x+3) then which statement is correct about (\left\(\frac{f}{g}\right\)(-3))?

Explanation opens after your attempt
Correct Answer

A. यह अपरिभाषित हैIt is undefined

Step 1

Concept

In \(\frac{f}{g}\) the denominator is (g(-3)=0) so the value is undefined. Check restrictions before simplifying \(\frac{x^2-9}{x+3}\).

Step 2

Why this answer is correct

The correct answer is A. यह अपरिभाषित है / It is undefined. In \(\frac{f}{g}\) the denominator is (g(-3)=0) so the value is undefined. Check restrictions before simplifying \(\frac{x^2-9}{x+3}\).

Step 3

Exam Tip

\(\frac{f}{g}\) में हर (g(-3)=0) है इसलिए मान अपरिभाषित है। \(\frac{x^2-9}{x+3}\) को सरल करने से पहले प्रतिबंध देखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-9) और (g(x)=x+3) हैं तो (\left\(\frac{f}{g}\right\)(-3)) के बारे में सही कथन क्या है? / If (f(x)=x-2-9) and (g(x)=x+3) then which statement is correct about (\left\(\frac{f}{g}\right\)(-3))?

Correct Answer: A. यह अपरिभाषित है / It is undefined. Explanation: \(\frac{f}{g}\) में हर (g(-3)=0) है इसलिए मान अपरिभाषित है। \(\frac{x^2-9}{x+3}\) को सरल करने से पहले प्रतिबंध देखें। / In \(\frac{f}{g}\) the denominator is (g(-3)=0) so the value is undefined. Check restrictions before simplifying \(\frac{x^2-9}{x+3}\).

Which concept should I revise for this Mathematics MCQ?

In \(\frac{f}{g}\) the denominator is (g(-3)=0) so the value is undefined. Check restrictions before simplifying \(\frac{x^2-9}{x+3}\).

What exam hint can help solve this Mathematics question?

\(\frac{f}{g}\) में हर (g(-3)=0) है इसलिए मान अपरिभाषित है। \(\frac{x^2-9}{x+3}\) को सरल करने से पहले प्रतिबंध देखें।