यदि (f(x)=x-2-5x+6) और (g(x)=x-2) हैं तो (\left\(\frac{f}{g}\right\)(x)) का प्रांत क्या है?

If (f(x)=x-2-5x+6) and (g(x)=x-2) then what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{2})

Step 1

Concept

The denominator is (x-2), so (x=2) is excluded even if the numerator has a common factor. Decide restrictions from the original denominator.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{2}). The denominator is (x-2), so (x=2) is excluded even if the numerator has a common factor. Decide restrictions from the original denominator.

Step 3

Exam Tip

हर (x-2) है इसलिए (x=2) हटेगा, भले ही अंश में समान गुणनखंड हो। मूल हर से प्रतिबंध तय करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-5x+6) और (g(x)=x-2) हैं तो (\left\(\frac{f}{g}\right\)(x)) का प्रांत क्या है? / If (f(x)=x-2-5x+6) and (g(x)=x-2) then what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Correct Answer: A. \(\mathbb{R}-{2}). Explanation: हर (x-2) है इसलिए (x=2) हटेगा, भले ही अंश में समान गुणनखंड हो। मूल हर से प्रतिबंध तय करें। / The denominator is (x-2), so (x=2) is excluded even if the numerator has a common factor. Decide restrictions from the original denominator.

Which concept should I revise for this Mathematics MCQ?

The denominator is (x-2), so (x=2) is excluded even if the numerator has a common factor. Decide restrictions from the original denominator.

What exam hint can help solve this Mathematics question?

हर (x-2) है इसलिए (x=2) हटेगा, भले ही अंश में समान गुणनखंड हो। मूल हर से प्रतिबंध तय करें।