Class 11 Mathematics Relations and Functions Algebra of real functions Medium Level 37

यदि (f(x)=x-2-4) और (g(x)=x+2) हों, तो (\left\(\frac{f}{g}\right\)(-2)) के बारे में सही कथन कौन सा है?

If (f(x)=x-2-4) and (g(x)=x+2), which statement is correct about (\left\(\frac{f}{g}\right\)(-2))?

Explanation opens after your attempt
Correct Answer

A. यह defined नहीं हैIt is not defined

Step 1

Concept

(g(-2)=0), so the quotient (\left\(\frac{f}{g}\right\)(-2)) is not defined. Even if the numerator is (0), a zero denominator is not allowed.

Step 2

Why this answer is correct

The correct answer is A. यह defined नहीं है / It is not defined. (g(-2)=0), so the quotient (\left\(\frac{f}{g}\right\)(-2)) is not defined. Even if the numerator is (0), a zero denominator is not allowed.

Step 3

Exam Tip

(g(-2)=0), इसलिए quotient (\left\(\frac{f}{g}\right\)(-2)) defined नहीं है। numerator भी (0) हो तो भी denominator (0) allowed नहीं होता।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-4) और (g(x)=x+2) हों, तो (\left\(\frac{f}{g}\right\)(-2)) के बारे में सही कथन कौन सा है? / If (f(x)=x-2-4) and (g(x)=x+2), which statement is correct about (\left\(\frac{f}{g}\right\)(-2))?

Correct Answer: A. यह defined नहीं है / It is not defined. Explanation: (g(-2)=0), इसलिए quotient (\left\(\frac{f}{g}\right\)(-2)) defined नहीं है। numerator भी (0) हो तो भी denominator (0) allowed नहीं होता। / (g(-2)=0), so the quotient (\left\(\frac{f}{g}\right\)(-2)) is not defined. Even if the numerator is (0), a zero denominator is not allowed.

Which concept should I revise for this Mathematics MCQ?

(g(-2)=0), so the quotient (\left\(\frac{f}{g}\right\)(-2)) is not defined. Even if the numerator is (0), a zero denominator is not allowed.

What exam hint can help solve this Mathematics question?

(g(-2)=0), इसलिए quotient (\left\(\frac{f}{g}\right\)(-2)) defined नहीं है। numerator भी (0) हो तो भी denominator (0) allowed नहीं होता।