यदि (f(x)=\sqrt{x-4}) और (g(x)=\sqrt{x+1}) हों, तो ((fg)(x)) का domain क्या होगा?

If (f(x)=\sqrt{x-4}) and (g(x)=\sqrt{x+1}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \([4,\infty\))

Step 1

Concept

For \(\sqrt{x-4}\), \(x\geq 4\), and for \(\sqrt{x+1}\), \(x\geq -1\). The intersection is \([4,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. \([4,\infty\)). For \(\sqrt{x-4}\), \(x\geq 4\), and for \(\sqrt{x+1}\), \(x\geq -1\). The intersection is \([4,\infty\)).

Step 3

Exam Tip

\(\sqrt{x-4}\) के लिए \(x\geq 4\) और \(\sqrt{x+1}\) के लिए \(x\geq -1\)। intersection \([4,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x-4}) और (g(x)=\sqrt{x+1}) हों, तो ((fg)(x)) का domain क्या होगा? / If (f(x)=\sqrt{x-4}) and (g(x)=\sqrt{x+1}), what is the domain of ((fg)(x))?

Correct Answer: A. \([4,\infty\)). Explanation: \(\sqrt{x-4}\) के लिए \(x\geq 4\) और \(\sqrt{x+1}\) के लिए \(x\geq -1\)। intersection \([4,\infty\)) है। / For \(\sqrt{x-4}\), \(x\geq 4\), and for \(\sqrt{x+1}\), \(x\geq -1\). The intersection is \([4,\infty\)).

Which concept should I revise for this Mathematics MCQ?

For \(\sqrt{x-4}\), \(x\geq 4\), and for \(\sqrt{x+1}\), \(x\geq -1\). The intersection is \([4,\infty\)).

What exam hint can help solve this Mathematics question?

\(\sqrt{x-4}\) के लिए \(x\geq 4\) और \(\sqrt{x+1}\) के लिए \(x\geq -1\)। intersection \([4,\infty\)) है।