यदि (f(x)=\sqrt{x+2}) और (g(x)=\frac{1}{x-1}) हों, तो ((f+g)(x)) का domain क्या है?
If (f(x)=\sqrt{x+2}) and (g(x)=\frac{1}{x-1}), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \([-2,\infty\)-{1})
Concept
For \(\sqrt{x+2}\), \(x\geq -2\), and for \(\frac{1}{x-1}\), \(x\neq 1\). Their intersection gives \([-2,\infty\)-{1}).
Why this answer is correct
The correct answer is A. \([-2,\infty\)-{1}). For \(\sqrt{x+2}\), \(x\geq -2\), and for \(\frac{1}{x-1}\), \(x\neq 1\). Their intersection gives \([-2,\infty\)-{1}).
Exam Tip
\(\sqrt{x+2}\) के लिए \(x\geq -2\) और \(\frac{1}{x-1}\) के लिए \(x\neq 1\)। intersection से domain \([-2,\infty\)-{1}) मिलता है।
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