यदि (f(x)=\sqrt{x+1}) और (g(x)=\sqrt{x-3}) हैं तो ((f-g)(x)) का प्रांत क्या है?

If (f(x)=\sqrt{x+1}) and (g(x)=\sqrt{x-3}) then what is the domain of ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. \([3,\infty))

Step 1

Concept

For both square roots \(x+1\ge 0\) and \(x-3\ge 0\), hence \(x\ge 3\). Even in subtraction both functions must be defined.

Step 2

Why this answer is correct

The correct answer is A. \([3,\infty)). For both square roots \(x+1\ge 0\) and \(x-3\ge 0\), hence \(x\ge 3\). Even in subtraction both functions must be defined.

Step 3

Exam Tip

दोनों वर्गमूलों के लिए \(x+1\ge 0\) और \(x-3\ge 0\), इसलिए \(x\ge 3\)। घटाव में भी दोनों फलन परिभाषित होने चाहिए।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x+1}) और (g(x)=\sqrt{x-3}) हैं तो ((f-g)(x)) का प्रांत क्या है? / If (f(x)=\sqrt{x+1}) and (g(x)=\sqrt{x-3}) then what is the domain of ((f-g)(x))?

Correct Answer: A. \([3,\infty)). Explanation: दोनों वर्गमूलों के लिए \(x+1\ge 0\) और \(x-3\ge 0\), इसलिए \(x\ge 3\)। घटाव में भी दोनों फलन परिभाषित होने चाहिए। / For both square roots \(x+1\ge 0\) and \(x-3\ge 0\), hence \(x\ge 3\). Even in subtraction both functions must be defined.

Which concept should I revise for this Mathematics MCQ?

For both square roots \(x+1\ge 0\) and \(x-3\ge 0\), hence \(x\ge 3\). Even in subtraction both functions must be defined.

What exam hint can help solve this Mathematics question?

दोनों वर्गमूलों के लिए \(x+1\ge 0\) और \(x-3\ge 0\), इसलिए \(x\ge 3\)। घटाव में भी दोनों फलन परिभाषित होने चाहिए।