यदि (f(x)=\frac{x-2-1}{x-2+1}) और (g(x)=\frac{2x}{x-2+1}) हैं तो (\(f^2+g^2\)(x)) का मान क्या है?
If (f(x)=\frac{x-2-1}{x-2+1}) and (g(x)=\frac{2x}{x-2+1}) then what is the value of (\(f^2+g^2\)(x))?
Explanation opens after your attempt
Correct Answer
A. (1)
Concept
Here (f-2(x)+g-2(x)=\frac{\(x^2-1\)2+(2x)2}{\(x^2+1\)2}=\frac{\(x^2+1\)2}{\(x^2+1\)2}=1). Recognise the identity while adding squares.
Why this answer is correct
The correct answer is A. (1). Here (f-2(x)+g-2(x)=\frac{\(x^2-1\)2+(2x)2}{\(x^2+1\)2}=\frac{\(x^2+1\)2}{\(x^2+1\)2}=1). Recognise the identity while adding squares.
Exam Tip
यहाँ (f-2(x)+g-2(x)=\frac{\(x^2-1\)2+(2x)2}{\(x^2+1\)2}=\frac{\(x^2+1\)2}{\(x^2+1\)2}=1)। वर्गों को जोड़ते समय सर्वसमिका पहचानें।
Login to save your score, XP, coins and progress.