यदि (f(x)=\frac{x+1}{x-2}) है, तो (f) का परिसर क्या है?
If (f(x)=\frac{x+1}{x-2}), what is the range of (f)?
Explanation opens after your attempt
Correct Answer
A. \( \mathbb{R}\setminus{1} \)
Concept
From \(y=\frac{x+1}{x-2}\), \(x=\frac{2y+1}{y-1}\), so \(y\ne 1\). For a linear fractional function, isolate the impossible value.
Why this answer is correct
The correct answer is A. \( \mathbb{R}\setminus{1} \). From \(y=\frac{x+1}{x-2}\), \(x=\frac{2y+1}{y-1}\), so \(y\ne 1\). For a linear fractional function, isolate the impossible value.
Exam Tip
\(y=\frac{x+1}{x-2}\) से \(x=\frac{2y+1}{y-1}\), इसलिए \(y\ne 1\)। रैखिक भिन्न फलन में असंभव मान अलग करें।
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