यदि (f(x)=\frac{1}{x-1}) और (g(x)=\frac{1}{x+1}) हैं, तो ((f+g)(x)) क्या है?
If (f(x)=\frac{1}{x-1}) and (g(x)=\frac{1}{x+1}), what is ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \( \frac{2x}{x^2-1} \)
Concept
(\frac{1}{x-1}+\frac{1}{x+1}=\frac{(x+1)+(x-1)}{x-2-1}=\frac{2x}{x-2-1}). Add the numerators correctly after taking the common denominator.
Why this answer is correct
The correct answer is A. \( \frac{2x}{x^2-1} \). (\frac{1}{x-1}+\frac{1}{x+1}=\frac{(x+1)+(x-1)}{x-2-1}=\frac{2x}{x-2-1}). Add the numerators correctly after taking the common denominator.
Exam Tip
(\frac{1}{x-1}+\frac{1}{x+1}=\frac{(x+1)+(x-1)}{x-2-1}=\frac{2x}{x-2-1})। जोड़ में अंशों को सही तरह जोड़ें।
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