यदि (f(x)=\frac{1}{x-1}) और (g(x)=\frac{1}{x+1}) हैं तो ((f+g)(x)) का प्रांत क्या है?

If (f(x)=\frac{1}{x-1}) and (g(x)=\frac{1}{x+1}) then what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-1,1})

Step 1

Concept

Both denominators cannot be zero so \(x\ne 1\) and \(x\ne -1\). For addition the common domain is the intersection of both domains.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-1,1}). Both denominators cannot be zero so \(x\ne 1\) and \(x\ne -1\). For addition the common domain is the intersection of both domains.

Step 3

Exam Tip

दोनों हर शून्य नहीं हो सकते इसलिए \(x\ne 1\) और \(x\ne -1\)। जोड़ में सामान्य प्रांत दोनों प्रांतों का प्रतिच्छेद होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x-1}) और (g(x)=\frac{1}{x+1}) हैं तो ((f+g)(x)) का प्रांत क्या है? / If (f(x)=\frac{1}{x-1}) and (g(x)=\frac{1}{x+1}) then what is the domain of ((f+g)(x))?

Correct Answer: A. \(\mathbb{R}-{-1,1}). Explanation: दोनों हर शून्य नहीं हो सकते इसलिए \(x\ne 1\) और \(x\ne -1\)। जोड़ में सामान्य प्रांत दोनों प्रांतों का प्रतिच्छेद होता है। / Both denominators cannot be zero so \(x\ne 1\) and \(x\ne -1\). For addition the common domain is the intersection of both domains.

Which concept should I revise for this Mathematics MCQ?

Both denominators cannot be zero so \(x\ne 1\) and \(x\ne -1\). For addition the common domain is the intersection of both domains.

What exam hint can help solve this Mathematics question?

दोनों हर शून्य नहीं हो सकते इसलिए \(x\ne 1\) और \(x\ne -1\)। जोड़ में सामान्य प्रांत दोनों प्रांतों का प्रतिच्छेद होता है।