यदि \(\binom{n}{1}+\binom{n}{2}=78\) है तो (n) का मान क्या है?
If \(\binom{n}{1}+\binom{n}{2}=78\), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
C. (12)
Concept
It gives (n+\frac{n(n-1)}{2}=78). Putting (n=12) gives (12+66=78).
Why this answer is correct
The correct answer is C. (12). It gives (n+\frac{n(n-1)}{2}=78). Putting (n=12) gives (12+66=78).
Exam Tip
यह (n+\frac{n(n-1)}{2}=78) देता है। (n=12) रखने पर (12+66=78) मिलता है।
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