यदि कुल (8) अक्षरों में (A) (2) बार और (B) (3) बार समान हों तो arrangements का formula क्या होगा?
If among (8) letters (A) is identical (2) times and (B) is identical (3) times what is the formula for arrangements?
Explanation opens after your attempt
Correct Answer
B. \(\frac{8!}{2!3!}\)
Concept
To remove internal orders of two repeated groups divide by (2!3!). In exams put the factorial of each repeated letter in the denominator.
Why this answer is correct
The correct answer is B. \(\frac{8!}{2!3!}\). To remove internal orders of two repeated groups divide by (2!3!). In exams put the factorial of each repeated letter in the denominator.
Exam Tip
दो repeated groups के internal orders हटाने के लिए (2!3!) से भाग देते हैं। परीक्षा में हर repeated letter का factorial denominator में रखें।
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