यदि \(A={x:x\in\mathbb{Z},;-3\le x\le 4}\) और \(B={x:x\in\mathbb{Z},;x^2<10}\), तो \(A\setminus B\) क्या है?

If \(A={x:x\in\mathbb{Z},;-3\le x\le 4}\) and \(B={x:x\in\mathbb{Z},;x^2<10}\), what is \(A\setminus B\)?

Explanation opens after your attempt
Correct Answer

A. ({4})

Step 1

Concept

Here \(B=\{-3,-2,-1,0,1,2,3\}\), and only (4) remains extra in (A). Build each set first, then take the difference.

Step 2

Why this answer is correct

The correct answer is A. ({4}). Here \(B=\{-3,-2,-1,0,1,2,3\}\), and only (4) remains extra in (A). Build each set first, then take the difference.

Step 3

Exam Tip

\(B=\{-3,-2,-1,0,1,2,3\}\) है और (A) में अतिरिक्त केवल (4) है। असमानता से सेट बनाकर फिर अंतर लें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in\mathbb{Z},;-3\le x\le 4}\) और \(B={x:x\in\mathbb{Z},;x^2<10}\), तो \(A\setminus B\) क्या है? / If \(A={x:x\in\mathbb{Z},;-3\le x\le 4}\) and \(B={x:x\in\mathbb{Z},;x^2<10}\), what is \(A\setminus B\)?

Correct Answer: A. ({4}). Explanation: \(B=\{-3,-2,-1,0,1,2,3\}\) है और (A) में अतिरिक्त केवल (4) है। असमानता से सेट बनाकर फिर अंतर लें। / Here \(B=\{-3,-2,-1,0,1,2,3\}\), and only (4) remains extra in (A). Build each set first, then take the difference.

Which concept should I revise for this Mathematics MCQ?

Here \(B=\{-3,-2,-1,0,1,2,3\}\), and only (4) remains extra in (A). Build each set first, then take the difference.

What exam hint can help solve this Mathematics question?

\(B=\{-3,-2,-1,0,1,2,3\}\) है और (A) में अतिरिक्त केवल (4) है। असमानता से सेट बनाकर फिर अंतर लें।