यदि \(A={x:x\in\mathbb{N},;x\le 12}\), \(B={x:x\in A,;x सम है}\), और (C={x:\(x\in A\),;x अभाज्य है\(}), तो (B\cup C) में कितने तत्व हैं\)?

If \(A={x:x\in\mathbb{N},;x\le 12}\), \(B={x:x\in A,;x is even}\), and (C={x:\(x\in A\),;x is prime\(}), how many elements are in (B\cup C)\)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

Here \(B=\{2,4,6,8,10,12\}\) and \(C=\{2,3,5,7,11\}\). Counting common (2) once gives (9) elements.

Step 2

Why this answer is correct

The correct answer is A. (9). Here \(B=\{2,4,6,8,10,12\}\) and \(C=\{2,3,5,7,11\}\). Counting common (2) once gives (9) elements.

Step 3

Exam Tip

\(B=\{2,4,6,8,10,12\}\) और \(C=\{2,3,5,7,11\}\) हैं। सामान्य (2) को एक बार गिनकर कुल (9) तत्व मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in\mathbb{N},;x\le 12}\), \(B={x:x\in A,;x सम है}\), और \(C={x:x\in A,;x अभाज्य है}\), तो \(B\cup C\) में कितने तत्व हैं? / If \(A={x:x\in\mathbb{N},;x\le 12}\), \(B={x:x\in A,;x is even}\), and (C={x:\(x\in A\),;x is prime\(}), how many elements are in (B\cup C)\)?

Correct Answer: A. (9). Explanation: \(B=\{2,4,6,8,10,12\}\) और \(C=\{2,3,5,7,11\}\) हैं। सामान्य (2) को एक बार गिनकर कुल (9) तत्व मिलते हैं। / Here \(B=\{2,4,6,8,10,12\}\) and \(C=\{2,3,5,7,11\}\). Counting common (2) once gives (9) elements.

Which concept should I revise for this Mathematics MCQ?

Here \(B=\{2,4,6,8,10,12\}\) and \(C=\{2,3,5,7,11\}\). Counting common (2) once gives (9) elements.

What exam hint can help solve this Mathematics question?

\(B=\{2,4,6,8,10,12\}\) और \(C=\{2,3,5,7,11\}\) हैं। सामान्य (2) को एक बार गिनकर कुल (9) तत्व मिलते हैं।