यदि \(A=\{r,s,t,u,v\}\), तो (\mathcal{P}(A)) के कितने तत्व ({r,s}) के अधिसमुच्चय हैं लेकिन (v) नहीं रखते?

If \(A=\{r,s,t,u,v\}\), how many elements of (\mathcal{P}(A)) are supersets of ({r,s}) but do not contain (v)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

(r,s) are fixed and (v) is excluded. The remaining (t,u) are free, so there are \(2^2=4\) subsets.

Step 2

Why this answer is correct

The correct answer is B. (4). (r,s) are fixed and (v) is excluded. The remaining (t,u) are free, so there are \(2^2=4\) subsets.

Step 3

Exam Tip

(r,s) निश्चित हैं और (v) नहीं लेना है। शेष (t,u) स्वतंत्र हैं, इसलिए \(2^2=4\) उपसमुच्चय होंगे।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{r,s,t,u,v\}\), तो (\mathcal{P}(A)) के कितने तत्व ({r,s}) के अधिसमुच्चय हैं लेकिन (v) नहीं रखते? / If \(A=\{r,s,t,u,v\}\), how many elements of (\mathcal{P}(A)) are supersets of ({r,s}) but do not contain (v)?

Correct Answer: B. (4). Explanation: (r,s) निश्चित हैं और (v) नहीं लेना है। शेष (t,u) स्वतंत्र हैं, इसलिए \(2^2=4\) उपसमुच्चय होंगे। / (r,s) are fixed and (v) is excluded. The remaining (t,u) are free, so there are \(2^2=4\) subsets.

Which concept should I revise for this Mathematics MCQ?

(r,s) are fixed and (v) is excluded. The remaining (t,u) are free, so there are \(2^2=4\) subsets.

What exam hint can help solve this Mathematics question?

(r,s) निश्चित हैं और (v) नहीं लेना है। शेष (t,u) स्वतंत्र हैं, इसलिए \(2^2=4\) उपसमुच्चय होंगे।