यदि \(A=\{a,b,c,d\}\) है, तो (\mathcal{P}(A)) में (a) को न रखने वाले subsets कितने हैं?

If \(A=\{a,b,c,d\}\), how many subsets in (\mathcal{P}(A)) do not contain (a)?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

When (a) is excluded, the remaining (3) elements are free, so there are \(2^3=8\) subsets. In exams, remove the excluded element and count.

Step 2

Why this answer is correct

The correct answer is B. (8). When (a) is excluded, the remaining (3) elements are free, so there are \(2^3=8\) subsets. In exams, remove the excluded element and count.

Step 3

Exam Tip

(a) excluded होने पर शेष (3) तत्व स्वतंत्र हैं, इसलिए \(2^3=8\) subsets हैं। परीक्षा में excluded element हटाकर गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{a,b,c,d\}\) है, तो (\mathcal{P}(A)) में (a) को न रखने वाले subsets कितने हैं? / If \(A=\{a,b,c,d\}\), how many subsets in (\mathcal{P}(A)) do not contain (a)?

Correct Answer: B. (8). Explanation: (a) excluded होने पर शेष (3) तत्व स्वतंत्र हैं, इसलिए \(2^3=8\) subsets हैं। परीक्षा में excluded element हटाकर गिनें। / When (a) is excluded, the remaining (3) elements are free, so there are \(2^3=8\) subsets. In exams, remove the excluded element and count.

Which concept should I revise for this Mathematics MCQ?

When (a) is excluded, the remaining (3) elements are free, so there are \(2^3=8\) subsets. In exams, remove the excluded element and count.

What exam hint can help solve this Mathematics question?

(a) excluded होने पर शेष (3) तत्व स्वतंत्र हैं, इसलिए \(2^3=8\) subsets हैं। परीक्षा में excluded element हटाकर गिनें।