यदि \(A=\{a,b,c,d,e\}\), तो (\mathcal{P}(A)) के कितने तत्वों में (a) और (b) में से ठीक एक होगा और (e) होगा?

If \(A=\{a,b,c,d,e\}\), how many elements of (\mathcal{P}(A)) contain exactly one of (a) and (b) and also contain (e)?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

There are (2) ways to choose exactly one of (a,b), and (e) is fixed. (c,d) are free, so \(2\times2^2=8\).

Step 2

Why this answer is correct

The correct answer is B. (8). There are (2) ways to choose exactly one of (a,b), and (e) is fixed. (c,d) are free, so \(2\times2^2=8\).

Step 3

Exam Tip

(a,b) में से ठीक एक चुनने के (2) तरीके हैं और (e) निश्चित है। (c,d) स्वतंत्र हैं, इसलिए \(2\times2^2=8\)।

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यदि \(A=\{a,b,c,d,e\}\), तो (\mathcal{P}(A)) के कितने तत्वों में (a) और (b) में से ठीक एक होगा और (e) होगा? / If \(A=\{a,b,c,d,e\}\), how many elements of (\mathcal{P}(A)) contain exactly one of (a) and (b) and also contain (e)?

Correct Answer: B. (8). Explanation: (a,b) में से ठीक एक चुनने के (2) तरीके हैं और (e) निश्चित है। (c,d) स्वतंत्र हैं, इसलिए \(2\times2^2=8\)। / There are (2) ways to choose exactly one of (a,b), and (e) is fixed. (c,d) are free, so \(2\times2^2=8\).

Which concept should I revise for this Mathematics MCQ?

There are (2) ways to choose exactly one of (a,b), and (e) is fixed. (c,d) are free, so \(2\times2^2=8\).

What exam hint can help solve this Mathematics question?

(a,b) में से ठीक एक चुनने के (2) तरीके हैं और (e) निश्चित है। (c,d) स्वतंत्र हैं, इसलिए \(2\times2^2=8\)।