यदि \(A=\{a,b,c,d,e\}\), तो (\mathcal{P}(A)) के कितने तत्वों में (a) और (b) में से ठीक एक होगा और (e) होगा?
If \(A=\{a,b,c,d,e\}\), how many elements of (\mathcal{P}(A)) contain exactly one of (a) and (b) and also contain (e)?
Explanation opens after your attempt
B. (8)
Concept
There are (2) ways to choose exactly one of (a,b), and (e) is fixed. (c,d) are free, so \(2\times2^2=8\).
Why this answer is correct
The correct answer is B. (8). There are (2) ways to choose exactly one of (a,b), and (e) is fixed. (c,d) are free, so \(2\times2^2=8\).
Exam Tip
(a,b) में से ठीक एक चुनने के (2) तरीके हैं और (e) निश्चित है। (c,d) स्वतंत्र हैं, इसलिए \(2\times2^2=8\)।
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