यदि \(A=\{a,b,c,d,e,f,g\}\) है, तो \(\mathcal{P}(A)\) में (4) तत्वों वाले ऐसे subsets कितने हैं जिनमें (a) हो और (b) न हो?

If \(A=\{a,b,c,d,e,f,g\}\), how many (4)-element subsets in \(\mathcal{P}(A)\) contain (a) and do not contain (b)?

Explanation opens after your attempt
Correct Answer

A. (10)

Step 1

Concept

(a) is fixed and (b) is excluded, so the remaining (3) elements must be chosen from (5) elements. The number is \(\binom{5}{3}=10\).

Step 2

Why this answer is correct

The correct answer is A. (10). (a) is fixed and (b) is excluded, so the remaining (3) elements must be chosen from (5) elements. The number is \(\binom{5}{3}=10\).

Step 3

Exam Tip

(a) fixed है और (b) excluded है, इसलिए बाकी (3) तत्व (5) तत्वों से चुनने होंगे। संख्या \(\binom{5}{3}=10\) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{a,b,c,d,e,f,g\}\) है, तो \(\mathcal{P}(A)\) में (4) तत्वों वाले ऐसे subsets कितने हैं जिनमें (a) हो और (b) न हो? / If \(A=\{a,b,c,d,e,f,g\}\), how many (4)-element subsets in \(\mathcal{P}(A)\) contain (a) and do not contain (b)?

Correct Answer: A. (10). Explanation: (a) fixed है और (b) excluded है, इसलिए बाकी (3) तत्व (5) तत्वों से चुनने होंगे। संख्या \(\binom{5}{3}=10\) है। / (a) is fixed and (b) is excluded, so the remaining (3) elements must be chosen from (5) elements. The number is \(\binom{5}{3}=10\).

Which concept should I revise for this Mathematics MCQ?

(a) is fixed and (b) is excluded, so the remaining (3) elements must be chosen from (5) elements. The number is \(\binom{5}{3}=10\).

What exam hint can help solve this Mathematics question?

(a) fixed है और (b) excluded है, इसलिए बाकी (3) तत्व (5) तत्वों से चुनने होंगे। संख्या \(\binom{5}{3}=10\) है।