यदि \(A=\{a,b,c,d\}\) और \(B=\{c,d,e,f\}\) हैं, तो (\(A\cup B\)\setminus \(A\cap B\)) क्या होगा?
If \(A=\{a,b,c,d\}\) and \(B=\{c,d,e,f\}\), what is (\(A\cup B\)\setminus \(A\cap B\))?
Explanation opens after your attempt
A. ( {a,b,e,f} )
Concept
\(A\cup B={a,b,c,d,e,f}\) and \(A\cap B={c,d}\), so the remaining elements are (a,b,e,f). This is a symmetric-difference type pattern.
Why this answer is correct
The correct answer is A. ( {a,b,e,f} ). \(A\cup B={a,b,c,d,e,f}\) and \(A\cap B={c,d}\), so the remaining elements are (a,b,e,f). This is a symmetric-difference type pattern.
Exam Tip
\(A\cup B={a,b,c,d,e,f}\) और \(A\cap B={c,d}\), इसलिए शेष (a,b,e,f) हैं। यह सममित अंतर जैसा पैटर्न है।
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