यदि (|A|=4), (|B|=5), और \(|A\cap B|=2\) है, तो \(|\mathcal{P}(A)\cap\mathcal{P}(B)|\) कितना होगा?
If (|A|=4), (|B|=5), and \(|A\cap B|=2\), what is \(|\mathcal{P}(A)\cap\mathcal{P}(B)|\)?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
(\mathcal{P}(A)\cap\mathcal{P}(B)=\mathcal{P}\(A\cap B\)), so the number is \(2^2=4\). This identity is very useful in exams.
Why this answer is correct
The correct answer is B. (4). (\mathcal{P}(A)\cap\mathcal{P}(B)=\mathcal{P}\(A\cap B\)), so the number is \(2^2=4\). This identity is very useful in exams.
Exam Tip
(\mathcal{P}(A)\cap\mathcal{P}(B)=\mathcal{P}\(A\cap B\)), इसलिए संख्या \(2^2=4\) है। परीक्षा में यह identity बहुत उपयोगी है।
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