यदि \(A=\{1,2,3,4,5\}\) है, तो (\mathcal{P}(A)) में ऐसे subsets कितने हैं जिनमें (1) हो लेकिन (2) न हो?
If \(A=\{1,2,3,4,5\}\), how many subsets in (\mathcal{P}(A)) contain (1) but not (2)?
Explanation opens after your attempt
Correct Answer
B. (8)
Concept
(1) is fixed and (2) is excluded, so the remaining (3) elements give \(2^3=8\) subsets. In exams, separate compulsory and forbidden elements.
Why this answer is correct
The correct answer is B. (8). (1) is fixed and (2) is excluded, so the remaining (3) elements give \(2^3=8\) subsets. In exams, separate compulsory and forbidden elements.
Exam Tip
(1) fixed है और (2) excluded है, इसलिए बाकी (3) तत्वों से \(2^3=8\) subsets बनेंगे। परीक्षा में compulsory और forbidden elements अलग करें।
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