यदि \(A=\{1,2,3,4,5\}\) है, तो (\mathcal{P}(A)) में ठीक (3) तत्व वाले समुच्चयों की संख्या कितनी है?
If \(A=\{1,2,3,4,5\}\), how many sets in (\mathcal{P}(A)) have exactly (3) elements?
Explanation opens after your attempt
Correct Answer
B. (10)
Concept
The number of ways to choose exactly (3) elements is \(\binom{5}{3}=10\). Each such choice is an element of (\mathcal{P}(A)).
Why this answer is correct
The correct answer is B. (10). The number of ways to choose exactly (3) elements is \(\binom{5}{3}=10\). Each such choice is an element of (\mathcal{P}(A)).
Exam Tip
ठीक (3) तत्व चुनने के तरीके \(\binom{5}{3}=10\) हैं। ऐसे हर चयन से (\mathcal{P}(A)) का एक तत्व बनता है।
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