यदि \(A=\{0,1,2,3\}\), तो (\mathcal{P}(A)) में वे कितने तत्व हैं जिनका योग (3) है?

If \(A=\{0,1,2,3\}\), how many elements of (\mathcal{P}(A)) have sum (3)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The subsets with sum (3) are ({3},{0,3},{1,2},{0,1,2}). Hence there are (4).

Step 2

Why this answer is correct

The correct answer is C. (4). The subsets with sum (3) are ({3},{0,3},{1,2},{0,1,2}). Hence there are (4).

Step 3

Exam Tip

योग (3) वाले उपसमुच्चय ({3},{0,3},{1,2},{0,1,2}) हैं। इसलिए कुल (4) हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{0,1,2,3\}\), तो (\mathcal{P}(A)) में वे कितने तत्व हैं जिनका योग (3) है? / If \(A=\{0,1,2,3\}\), how many elements of (\mathcal{P}(A)) have sum (3)?

Correct Answer: C. (4). Explanation: योग (3) वाले उपसमुच्चय ({3},{0,3},{1,2},{0,1,2}) हैं। इसलिए कुल (4) हैं। / The subsets with sum (3) are ({3},{0,3},{1,2},{0,1,2}). Hence there are (4).

Which concept should I revise for this Mathematics MCQ?

The subsets with sum (3) are ({3},{0,3},{1,2},{0,1,2}). Hence there are (4).

What exam hint can help solve this Mathematics question?

योग (3) वाले उपसमुच्चय ({3},{0,3},{1,2},{0,1,2}) हैं। इसलिए कुल (4) हैं।