(9) सफेद और (10) काली गेंदों में से (6) गेंदें चुननी हैं जिनमें सभी गेंदों का रंग समान न हो। कितने तरीके हैं?
From (9) white and (10) black balls (6) balls are to be selected such that all balls are not of the same color. How many ways are there?
Explanation opens after your attempt
Correct Answer
A. (26838)
Concept
Total ways are \(\binom{19}{6}=27132\). Removing all-white \(\binom{9}{6}=84\) and all-black \(\binom{10}{6}=210\) gives (26838).
Why this answer is correct
The correct answer is A. (26838). Total ways are \(\binom{19}{6}=27132\). Removing all-white \(\binom{9}{6}=84\) and all-black \(\binom{10}{6}=210\) gives (26838).
Exam Tip
कुल \(\binom{19}{6}=27132\) हैं। सभी सफेद \(\binom{9}{6}=84\) और सभी काली \(\binom{10}{6}=210\) हटाने पर (26838) मिलते हैं।
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