(6) लाल और (5) नीली गेंदों में से (4) गेंदें चुननी हैं जिनमें कम से कम (2) लाल गेंदें हों। कितने तरीके हैं?
From (6) red and (5) blue balls (4) balls are to be selected with at least (2) red balls. How many ways are there?
Explanation opens after your attempt
Correct Answer
B. (275)
Concept
The cases are (2), (3), and (4) red balls. The total is \(\binom{6}{2}\binom{5}{2}+\binom{6}{3}\binom{5}{1}+\binom{6}{4}=275\).
Why this answer is correct
The correct answer is B. (275). The cases are (2), (3), and (4) red balls. The total is \(\binom{6}{2}\binom{5}{2}+\binom{6}{3}\binom{5}{1}+\binom{6}{4}=275\).
Exam Tip
मामले (2), (3) और (4) लाल गेंदों के हैं। कुल \(\binom{6}{2}\binom{5}{2}+\binom{6}{3}\binom{5}{1}+\binom{6}{4}=275\) है।
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