(16) छात्रों में से (7) छात्रों का चयन करना है। (5) विशेष छात्रों में से कम से कम (2) शामिल हों। कितने तरीके हैं?

From (16) students (7) students are to be selected. At least (2) of (5) special students must be included. How many ways are there?

Explanation opens after your attempt
Correct Answer

C. (8800)

Step 1

Concept

Total ways are \(\binom{16}{7}=11440\). Removing selections with (0) and (1) special student gives \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\).

Step 2

Why this answer is correct

The correct answer is C. (8800). Total ways are \(\binom{16}{7}=11440\). Removing selections with (0) and (1) special student gives \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\).

Step 3

Exam Tip

कुल \(\binom{16}{7}=11440\) हैं। (0) और (1) विशेष वाले चयन हटाने पर \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\) है।

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Mathematics Answer, Explanation and Revision Hints

(16) छात्रों में से (7) छात्रों का चयन करना है। (5) विशेष छात्रों में से कम से कम (2) शामिल हों। कितने तरीके हैं? / From (16) students (7) students are to be selected. At least (2) of (5) special students must be included. How many ways are there?

Correct Answer: C. (8800). Explanation: कुल \(\binom{16}{7}=11440\) हैं। (0) और (1) विशेष वाले चयन हटाने पर \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\) है। / Total ways are \(\binom{16}{7}=11440\). Removing selections with (0) and (1) special student gives \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\).

Which concept should I revise for this Mathematics MCQ?

Total ways are \(\binom{16}{7}=11440\). Removing selections with (0) and (1) special student gives \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\).

What exam hint can help solve this Mathematics question?

कुल \(\binom{16}{7}=11440\) हैं। (0) और (1) विशेष वाले चयन हटाने पर \(11440-\binom{11}{7}-\binom{5}{1}\binom{11}{6}=8800\) है।