(13) छात्रों में से (6) छात्रों का चयन करना है। (5) विशेष छात्रों में से कम से कम (1) शामिल हो। कितने तरीके हैं?

From (13) students (6) students are to be selected. At least (1) of (5) special students must be included. How many ways are there?

Explanation opens after your attempt
Correct Answer

D. (3003)

Step 1

Concept

Total ways are \(\binom{13}{6}=1716\) and ways with no special student are \(\binom{8}{6}=28\). Hence (1716-28=1688) ways.

Step 2

Why this answer is correct

The correct answer is D. (3003). Total ways are \(\binom{13}{6}=1716\) and ways with no special student are \(\binom{8}{6}=28\). Hence (1716-28=1688) ways.

Step 3

Exam Tip

कुल \(\binom{13}{6}=1716\) हैं और कोई विशेष न हो तो \(\binom{8}{6}=28\) हैं। इसलिए (1716-28=1688) तरीके हैं।

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(13) छात्रों में से (6) छात्रों का चयन करना है। (5) विशेष छात्रों में से कम से कम (1) शामिल हो। कितने तरीके हैं? / From (13) students (6) students are to be selected. At least (1) of (5) special students must be included. How many ways are there?

Correct Answer: D. (3003). Explanation: कुल \(\binom{13}{6}=1716\) हैं और कोई विशेष न हो तो \(\binom{8}{6}=28\) हैं। इसलिए (1716-28=1688) तरीके हैं। / Total ways are \(\binom{13}{6}=1716\) and ways with no special student are \(\binom{8}{6}=28\). Hence (1716-28=1688) ways.

Which concept should I revise for this Mathematics MCQ?

Total ways are \(\binom{13}{6}=1716\) and ways with no special student are \(\binom{8}{6}=28\). Hence (1716-28=1688) ways.

What exam hint can help solve this Mathematics question?

कुल \(\binom{13}{6}=1716\) हैं और कोई विशेष न हो तो \(\binom{8}{6}=28\) हैं। इसलिए (1716-28=1688) तरीके हैं।