वृत्त पर (10) समान दूरी वाले बिंदुओं में से (3) बिंदु चुनने हैं ताकि कोई दो चुने हुए बिंदु आसन्न न हों। कितने चयन संभव हैं?
From (10) equally spaced points on a circle, (3) points are to be chosen so that no two chosen points are adjacent. How many selections are possible?
Explanation opens after your attempt
C. (50)
Concept
For circular selection, the count is \(\frac{10}{10-3}\times{}^{7}C_{3}\). Its value is (50).
Why this answer is correct
The correct answer is C. (50). For circular selection, the count is \(\frac{10}{10-3}\times{}^{7}C_{3}\). Its value is (50).
Exam Tip
वृत्तीय चयन में संख्या \(\frac{10}{10-3}\times{}^{7}C_{3}\) है। इसका मान (50) है।
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