वृत्त पर (10) समान दूरी वाले बिंदुओं में से (3) बिंदु चुनने हैं ताकि कोई दो चुने हुए बिंदु आसन्न न हों। कितने चयन संभव हैं?

From (10) equally spaced points on a circle, (3) points are to be chosen so that no two chosen points are adjacent. How many selections are possible?

Explanation opens after your attempt
Correct Answer

C. (50)

Step 1

Concept

For circular selection, the count is \(\frac{10}{10-3}\times{}^{7}C_{3}\). Its value is (50).

Step 2

Why this answer is correct

The correct answer is C. (50). For circular selection, the count is \(\frac{10}{10-3}\times{}^{7}C_{3}\). Its value is (50).

Step 3

Exam Tip

वृत्तीय चयन में संख्या \(\frac{10}{10-3}\times{}^{7}C_{3}\) है। इसका मान (50) है।

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Mathematics Answer, Explanation and Revision Hints

वृत्त पर (10) समान दूरी वाले बिंदुओं में से (3) बिंदु चुनने हैं ताकि कोई दो चुने हुए बिंदु आसन्न न हों। कितने चयन संभव हैं? / From (10) equally spaced points on a circle, (3) points are to be chosen so that no two chosen points are adjacent. How many selections are possible?

Correct Answer: C. (50). Explanation: वृत्तीय चयन में संख्या \(\frac{10}{10-3}\times{}^{7}C_{3}\) है। इसका मान (50) है। / For circular selection, the count is \(\frac{10}{10-3}\times{}^{7}C_{3}\). Its value is (50).

Which concept should I revise for this Mathematics MCQ?

For circular selection, the count is \(\frac{10}{10-3}\times{}^{7}C_{3}\). Its value is (50).

What exam hint can help solve this Mathematics question?

वृत्तीय चयन में संख्या \(\frac{10}{10-3}\times{}^{7}C_{3}\) है। इसका मान (50) है।