असमानताओं \(x+2y\leq 8\), \(2x+y\leq 8\), \(x\geq 0\), \(y\geq 0\) से बने क्षेत्र में वह शीर्ष कौन-सा है जहां दोनों तिरछी रेखाएं मिलती हैं?
For the region formed by \(x+2y\leq 8\), \(2x+y\leq 8\), \(x\geq 0\), \(y\geq 0\), which vertex is the intersection of the two oblique boundary lines?
Explanation opens after your attempt
B. बिंदु (\left\(\frac{8}{3},\frac{8}{3}\right\))Point (\left\(\frac{8}{3},\frac{8}{3}\right\))
Concept
Solving the two boundary lines together gives \(x=y=\frac{8}{3}\). In exams, find vertices by treating boundary lines as equations.
Why this answer is correct
The correct answer is B. बिंदु (\left\(\frac{8}{3},\frac{8}{3}\right\)) / Point (\left\(\frac{8}{3},\frac{8}{3}\right\)). Solving the two boundary lines together gives \(x=y=\frac{8}{3}\). In exams, find vertices by treating boundary lines as equations.
Exam Tip
दोनों रेखाओं को साथ हल करने पर \(x=y=\frac{8}{3}\) मिलता है। परीक्षा में शीर्ष निकालने के लिए सीमा रेखाओं को समीकरण मानें।
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