फलन (f(x)=\operatorname{sgn}(3x-12)) में (x>4) होने पर मान क्या होगा?
For (f(x)=\operatorname{sgn}(3x-12)), what is the value when (x>4)?
Explanation opens after your attempt
A. (1)
Concept
If (x>4), then (3x-12>0). Therefore the signum value is (1).
Why this answer is correct
The correct answer is A. (1). If (x>4), then (3x-12>0). Therefore the signum value is (1).
Exam Tip
यदि (x>4), तो (3x-12>0)। इसलिए साइनम मान (1) है।
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