फलन (f(x)=\operatorname{sgn}(3x-12)) में (x>4) होने पर मान क्या होगा?

For (f(x)=\operatorname{sgn}(3x-12)), what is the value when (x>4)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

If (x>4), then (3x-12>0). Therefore the signum value is (1).

Step 2

Why this answer is correct

The correct answer is A. (1). If (x>4), then (3x-12>0). Therefore the signum value is (1).

Step 3

Exam Tip

यदि (x>4), तो (3x-12>0)। इसलिए साइनम मान (1) है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\operatorname{sgn}(3x-12)) में (x>4) होने पर मान क्या होगा? / For (f(x)=\operatorname{sgn}(3x-12)), what is the value when (x>4)?

Correct Answer: A. (1). Explanation: यदि (x>4), तो (3x-12>0)। इसलिए साइनम मान (1) है। / If (x>4), then (3x-12>0). Therefore the signum value is (1).

Which concept should I revise for this Mathematics MCQ?

If (x>4), then (3x-12>0). Therefore the signum value is (1).

What exam hint can help solve this Mathematics question?

यदि (x>4), तो (3x-12>0)। इसलिए साइनम मान (1) है।