(8) व्यक्तियों में से (3) व्यक्तियों की समिति बनानी है लेकिन (2) विशेष व्यक्ति साथ में नहीं चुने जा सकते। कितने तरीके होंगे?

A committee of (3) persons is to be formed from (8) persons but (2) special persons cannot be selected together. How many ways are possible?

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Correct Answer

C. (48)

Step 1

Concept

Total ways are \(\binom{8}{3}=56\) and if both special persons are together the third person is chosen in (6) ways. Hence the valid count is (50).

Step 2

Why this answer is correct

The correct answer is C. (48). Total ways are \(\binom{8}{3}=56\) and if both special persons are together the third person is chosen in (6) ways. Hence the valid count is (50).

Step 3

Exam Tip

कुल \(\binom{8}{3}=56\) हैं और दोनों विशेष साथ हों तो तीसरा व्यक्ति (6) तरीकों से चुनेगा। इसलिए (56-6=50) नहीं बल्कि सही उत्तर (50) है।

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Mathematics Answer, Explanation and Revision Hints

(8) व्यक्तियों में से (3) व्यक्तियों की समिति बनानी है लेकिन (2) विशेष व्यक्ति साथ में नहीं चुने जा सकते। कितने तरीके होंगे? / A committee of (3) persons is to be formed from (8) persons but (2) special persons cannot be selected together. How many ways are possible?

Correct Answer: C. (48). Explanation: कुल \(\binom{8}{3}=56\) हैं और दोनों विशेष साथ हों तो तीसरा व्यक्ति (6) तरीकों से चुनेगा। इसलिए (56-6=50) नहीं बल्कि सही उत्तर (50) है। / Total ways are \(\binom{8}{3}=56\) and if both special persons are together the third person is chosen in (6) ways. Hence the valid count is (50).

Which concept should I revise for this Mathematics MCQ?

Total ways are \(\binom{8}{3}=56\) and if both special persons are together the third person is chosen in (6) ways. Hence the valid count is (50).

What exam hint can help solve this Mathematics question?

कुल \(\binom{8}{3}=56\) हैं और दोनों विशेष साथ हों तो तीसरा व्यक्ति (6) तरीकों से चुनेगा। इसलिए (56-6=50) नहीं बल्कि सही उत्तर (50) है।