एक बैग में (5) अलग लाल और (7) अलग काली गेंदें हैं। (4) गेंदें चुननी हैं जिनमें रंग समान न हो। कितने चयन होंगे?

A bag has (5) distinct red and (7) distinct black balls. (4) balls are to be selected such that not all are of the same color. How many selections are possible?

Explanation opens after your attempt
Correct Answer

C. (455)

Step 1

Concept

Subtract all-red \(^{5}C_{4}=5\) and all-black \(^{7}C_{4}=35\) from total \(^{12}C_{4}=495\). Answer (455).

Step 2

Why this answer is correct

The correct answer is C. (455). Subtract all-red \(^{5}C_{4}=5\) and all-black \(^{7}C_{4}=35\) from total \(^{12}C_{4}=495\). Answer (455).

Step 3

Exam Tip

कुल \(^{12}C_{4}=495\) से सभी लाल \(^{5}C_{4}=5\) और सभी काली \(^{7}C_{4}=35\) हटाएं। उत्तर (455)।

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Mathematics Answer, Explanation and Revision Hints

एक बैग में (5) अलग लाल और (7) अलग काली गेंदें हैं। (4) गेंदें चुननी हैं जिनमें रंग समान न हो। कितने चयन होंगे? / A bag has (5) distinct red and (7) distinct black balls. (4) balls are to be selected such that not all are of the same color. How many selections are possible?

Correct Answer: C. (455). Explanation: कुल \(^{12}C_{4}=495\) से सभी लाल \(^{5}C_{4}=5\) और सभी काली \(^{7}C_{4}=35\) हटाएं। उत्तर (455)। / Subtract all-red \(^{5}C_{4}=5\) and all-black \(^{7}C_{4}=35\) from total \(^{12}C_{4}=495\). Answer (455).

Which concept should I revise for this Mathematics MCQ?

Subtract all-red \(^{5}C_{4}=5\) and all-black \(^{7}C_{4}=35\) from total \(^{12}C_{4}=495\). Answer (455).

What exam hint can help solve this Mathematics question?

कुल \(^{12}C_{4}=495\) से सभी लाल \(^{5}C_{4}=5\) और सभी काली \(^{7}C_{4}=35\) हटाएं। उत्तर (455)।