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If (f:\mathbb{R}\to\mathbb{R}) is given by (f(x)=\begin{cases}4x-5,&x\le2\x+1,&x\ge2\end{cases}), which statement is correct?यदि (f:\mathbb{R}\to\mathbb{R}) को (f(x)=\begin{cases}4x-5,&x\le2\x+1,&x\ge2\end{cases}) से दिया गया है, तो सही कथन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: It is a function because both rules give (3) at (x=2)यह फलन है क्योंकि (x=2) पर दोनों नियम (3) देते हैं
At (x=2), (4\cdot2-5=3) and (2+1=3), so there is no conflict. Overlap is valid when both values agree.(x=2) पर (4\cdot2-5=3) और (2+1=3) हैं, इसलिए कोई विरोध नहीं है। ओवरलैप तब मान्य है जब दोनों मान समान हों।
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