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If (R={(x,y):y=\frac{3}{x+2},\ x\in{-3,-2,-1},\ y\in\mathbb{R}}) is considered from (X={-3,-2,-1}) to (\mathbb{R}), what is correct?

Answer and explanation

Correct answer: It is not a function because the value at (x=-2) is undefined

The domain includes (-2), but (\frac{3}{-2+2}) is undefined. A function needs a value at every domain element.

Related tags

Undefined ValueDomainFunction TestFunctions As A Special Kind Of RelationRelations And FunctionsMathematicsClass 11 Mcq

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