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If \(A=\{1,2,3,4,5\}\) and \(B=\{a,b,c,d,e,f\}\), how many functions from \(A\) to \(B\) have distinct images for all five elements of \(A\)?

Answer and explanation

Correct answer: 720

Having distinct images for all five elements means that the function must be injective. There are 6 choices for the image of the first element, followed by 5, 4, 3 and 2 choices. Hence, the total number of functions is \(6\times5\times4\times3\times2={}^6P_5=720\). Since the assignment of images to the elements matters, use a permutation rather than a combination.

Related tags

Relations And FunctionsInjective FunctionsFinite FunctionsPermutationsCountingFunctions As A Special Kind Of RelationMathematicsClass 11 Mcq

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