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If \(A=\{1,2,3,4,5,6,7\}\) and \(B=\{0,1\}\), how many functions from \(A\) to \(B\) have exactly 4 elements of \(A\) mapped to 1?

Answer and explanation

Correct answer: 35

We must choose the 4 elements of the 7-element domain that will be mapped to 1. This can be done in \(\binom{7}{4}=35\) ways. The remaining 3 elements must be mapped to 0, so they introduce no additional choices. Hence the number of functions is 35. Exam tip: For a function from an \(n\)-element set to \(\{0,1\}\), if exactly \(r\) domain elements map to 1, the count is \(\binom{n}{r}\).

Related tags

Binary FunctionsCombinationsRelations And FunctionsCountingFunctions As A Special Kind Of RelationMathematicsClass 11 Mcq

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