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If (f:\mathbb{R}-{4}\to\mathbb{R}) is given by (f(x)=\frac{x^2-16}{x-4}), which value will not belong to the range?यदि (f:\mathbb{R}-{4}\to\mathbb{R}) को (f(x)=\frac{x^2-16}{x-4}) से दिया गया है, तो कौन सा मान परिसर में नहीं आएगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
On the given domain (f(x)=x+4), but removing (x=4) removes the value (8). After simplification, the image of the excluded input is removed.दिए गए प्रांत पर (f(x)=x+4) है, लेकिन (x=4) हटने से मान (8) नहीं मिलता। सरलीकरण के बाद हटे हुए इनपुट की छवि हट जाती है।
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