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If (f:\mathbb{R}\to\mathbb{R}) is given by (f(x)=\frac{x^2+1}{x^2+2}), what is the range?यदि (f:\mathbb{R}\to\mathbb{R}) को (f(x)=\frac{x^2+1}{x^2+2}) से दिया गया है तो परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\left[\frac{1}{2},1\right))(\left[\frac{1}{2},1\right))
The value is (1-\frac{1}{x^2+2}), so the minimum is (\frac{1}{2}) and (1) is never attained. The range is (\left[\frac{1}{2},1\right)).मान (1-\frac{1}{x^2+2}) है, इसलिए न्यूनतम (\frac{1}{2}) और (1) कभी नहीं मिलता। परिसर (\left[\frac{1}{2},1\right)) है।
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