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If (f:[0,4]\to\mathbb{R}) is given by (f(x)=\sqrt{x}+\sqrt{4-x}), what is the maximum value of (f)?यदि (f:[0,4]\to\mathbb{R}) को (f(x)=\sqrt{x}+\sqrt{4-x}) से दिया गया है तो (f) का अधिकतम मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2\sqrt{2})(2\sqrt{2})
By symmetry the maximum occurs at (x=2) and equals (2\sqrt{2}). In such questions check the balanced point.सममिति से अधिकतम (x=2) पर मिलता है और मान (2\sqrt{2}) है। ऐसे प्रश्नों में संतुलित बिंदु जांचें।
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