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If (f:\mathbb{R}-{2}\to\mathbb{R}) is given by (f(x)=\frac{x^2-4}{x-2}), what is the range?यदि (f:\mathbb{R}-{2}\to\mathbb{R}) को (f(x)=\frac{x^2-4}{x-2}) से दिया गया है तो परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\mathbb{R}-{4})(\mathbb{R}-{4})
On the given domain (f(x)=x+2), but removing (x=2) removes the value (4). Check how a removed point affects the range.दिए गए प्रांत पर (f(x)=x+2) है लेकिन (x=2) हटने से मान (4) नहीं मिलता। हटे हुए बिंदु का प्रभाव परिसर पर देखें।
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