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A function (f:\mathbb{R}\to\mathbb{R}) is to be defined by (f(x)=\sqrt{ax^2+4}). What is the correct condition on (a) for it to be a function on all of (\mathbb{R})?

Answer and explanation

Correct answer: (\ a\ge0) / (a\ge0)

The expression (ax^2+4) stays non-negative for all (x\in\mathbb{R}) only when (a\ge0). In square-root functions the radicand must be non-negative.

Related tags

DomainParameterSquare RootFunctions As A Special Kind Of RelationRelations And FunctionsMathematicsClass 11 Mcq

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