0 reads0 ratings0 helpful
If (f:\mathbb{R}\to[0,\infty)) is given by (f(x)=x^2+2x+2), what is the range?यदि (f:\mathbb{R}\to[0,\infty)) को (f(x)=x^2+2x+2) से दिया गया है, तो परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([1,\infty))([1,\infty))
Since (x^2+2x+2=(x+1)^2+1), the minimum value is (1). Completing the square is useful for finding range.(x^2+2x+2=(x+1)^2+1), इसलिए न्यूनतम मान (1) है। वर्ग पूरा करना परिसर निकालने का उपयोगी तरीका है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
