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Which piecewise rule will not define a function on (\mathbb{R})?निम्न में से किस खंडित नियम से (\mathbb{R}) पर फलन नहीं बनेगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (f(x)=\begin{cases}x^2,&x\le2\x+3,&x\ge2\end{cases})(f(x)=\begin{cases}x^2,&x\le2\x+3,&x\ge2\end{cases})
In option (C), (x=2) belongs to both rules and gives values (4) and (5). Two values for one input do not define a function.विकल्प (C) में (x=2) दोनों नियमों में आता है और मान (4) तथा (5) मिलते हैं। एक ही इनपुट पर दो मान फलन नहीं बनाते।
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