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If (f:\mathbb{R}\to\mathbb{R}) is given by (f(x)=\begin{cases}x+1,&x<0\x^2,&x\ge0\end{cases}), what is (f(0))?यदि (f:\mathbb{R}\to\mathbb{R}) को (f(x)=\begin{cases}x+1,&x<0\x^2,&x\ge0\end{cases}) से दिया गया है, तो (f(0)) क्या होगा?
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Correct answer:सही उत्तर: (0)(0)
Since (0\ge0), the second rule applies and (f(0)=0^2=0). In piecewise functions read the boundary symbol carefully.(0\ge0) है, इसलिए दूसरा नियम लागू होगा और (f(0)=0^2=0)। खंडित फलन में सीमा चिह्न ध्यान से पढ़ें।
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