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If (f:\mathbb{R}\to\mathbb{R}) is to be given by (f(x)=\sqrt{4-x^2}), which is the correct domain?यदि (f:\mathbb{R}\to\mathbb{R}) को (f(x)=\sqrt{4-x^2}) से देना हो, तो सही प्रांत कौन सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-2,2])([-2,2])
For real values, (4-x^2\ge0), so (-2\le x\le2). In square-root questions keep the radicand non-negative.वास्तविक मान के लिए (4-x^2\ge0), इसलिए (-2\le x\le2)। मूल वाले प्रश्नों में भीतर की राशि अऋण रखें।
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