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If (R={(x,y)\in\mathbb{R}\times\mathbb{R}:y=\sqrt{x}}) is considered from (\mathbb{R}) to (\mathbb{R}), why is it not a function?यदि (R={(x,y)\in\mathbb{R}\times\mathbb{R}:y=\sqrt{x}}) को (\mathbb{R}) से (\mathbb{R}) में माना जाए, तो यह फलन क्यों नहीं है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Because for (x<0), (\sqrt{x}) is not realक्योंकि (x<0) के लिए (\sqrt{x}) वास्तविक नहीं है
With the whole (\mathbb{R}) as domain, negative (x)-values have no real image. Hence it is not a function on the given domain.पूरे (\mathbb{R}) को प्रांत लेने पर ऋणात्मक (x) के लिए वास्तविक मान नहीं मिलता। इसलिए यह दिए गए प्रांत पर फलन नहीं है।
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