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If the function \(f:\{1,2,3,4\}\to\{1,2\}\) is defined by \(f(x)=1\) when \(x<2\) and \(f(x)=2\) when \(x\ge 2\), what is the value of \(f(2)\)?

Answer and explanation

Correct answer: 2

For \(x=2\), the condition \(2<2\) is false, while \(2\ge 2\) is true. Therefore, \(f(2)=2\). Remember that \(\ge\) includes equality, so the boundary point \(x=2\) belongs to the second case.

Related tags

Relations-FunctionsPiecewise-FunctionBoundary-ValueFunctions As A Special Kind Of RelationRelations And FunctionsMathematicsClass 11 Mcq

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