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If f:R → R is defined by f(x) = 1/x, which reason prevents it from being a function on all of R?

Answer and explanation

Correct answer: 1/x is not defined at x = 0

For a mapping f:A→B to be a function, every element of the stated domain A must have exactly one image in B. Here the claimed domain is all real numbers, but the rule f(x)=1/x contains division by x. Division by zero is undefined, so f(0)=1/0 has no real value. Consequently, the rule cannot define a function on all of R; its natural real domain is R extbackslash{0}. For every nonzero real x, the rule gives exactly one real output, so there is no problem at x=1 or x=−1. Option D is also false because no nonzero input has two images. Therefore option A correctly identifies the exceptional domain value and the precise reason the proposed mapping fails.

Related tags

Relations And FunctionsDomainUndefined ExpressionFunctions As A Special Kind Of RelationMathematicsClass 11 Mcq

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