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In Class 11 Mathematics, this topic explains how the formulas in Permutations and Combinations are derived and how they are connected. Students learn the meaning of factorial notation, develop the formulas for nPr and nCr from counting principles, and understand why nPr = r! nCr and nCr = nC(n−r). The topic also shows when to use arrangements or selections, helping students apply these relationships logically instead of relying on memorized formulas.
Practice questions
01 What is the counting interpretation of ({}^{n}C_r=\frac{n}{r}{}^{n-1}C_{r-1})?
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Answer and explanation
Correct answer: A. First choose one marked member and then choose remaining (r-1)
Explanation: Choose the marked member in (n) ways and remove overcount of (r) possible marks. In exams understand such identities by member marking.
10 When (8) distinct objects are divided into unlabelled groups of sizes (3), (3), and (2), by what extra factor do we divide?
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Answer and explanation
Correct answer: A. (2!)
Explanation: Two groups have equal size (3), so interchanging those groups gives the same distribution. In exams divide extra by factorial of equal-sized unlabelled groups.
17 What is the formula for choosing (r) objects from (n) objects with exactly (s) special objects?
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Answer and explanation
Correct answer: A. (^{a}C_s\cdot{}^{n-a}C_{r-s}) where there are (a) special objects
Explanation: Choose (s) objects from the special group and (r-s) from the non-special group. In exams split exactly conditions into product of choices.
21 Arrange (8) people in a row so that (A) and (B) are not together. Which formula gives the count?
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Answer and explanation
Correct answer: A. (8!-7!\cdot2!)
Explanation: Subtract block arrangements where (A) and (B) are together from total arrangements. In exams complement is easy for not-together permutations.
24 Under which condition does the repeated-object arrangement formula (\frac{n!}{p!q!}) apply?
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Answer and explanation
Correct answer: A. Among (n) objects, (p) of one type and (q) of another type are identical
Explanation: Internal permutations of same-type objects do not create new arrangements. In exams derive repeated-letter counts using factorial division.
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