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What are the vertices of the solution region of \(x\geq 0\), \(y\geq 0\), \(x+2y\leq 10\), and \(3x+y\leq 12\)?असमानताओं \(x\geq 0\), \(y\geq 0\), \(x+2y\leq 10\), \(3x+y\leq 12\) के हल-क्षेत्र के शीर्ष कौन से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((0,0)), ((4,0)), \(\left(\frac{14}{5},\frac{18}{5}\right)\), ((0,5))((0,0)), ((4,0)), \(\left(\frac{14}{5},\frac{18}{5}\right)\), ((0,5))
The slant boundaries intersect at \(\left(\frac{14}{5},\frac{18}{5}\right)\). Use valid intercepts on the axes to list all corners.दोनों तिरछी सीमाओं का प्रतिच्छेद \(\left(\frac{14}{5},\frac{18}{5}\right)\) है। अक्षों पर वैध अवरोध लेकर सभी कोने चुनें।
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